SOLUTION: How do I find the solution set from y= x^2 - 22 and y = 4x - 1? I don't know how to factoring x^2 - 22. As for the second linear I'm pretty sure it's (-1/4, -1) Thank you

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: How do I find the solution set from y= x^2 - 22 and y = 4x - 1? I don't know how to factoring x^2 - 22. As for the second linear I'm pretty sure it's (-1/4, -1) Thank you      Log On


   

Question 765313: How do I find the solution set from y= x^2 - 22 and y = 4x - 1?
I don't know how to factoring x^2 - 22. As for the second linear I'm pretty sure it's (-1/4, -1)
Thank you
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Factoring the quadratic equation first is unnecessary. Try substitution. You have a formula for y in the form of the linear equation, so substitute this into the quadratic equation, and then solve for x that way.

y=x%5E2-22
4x-1=x%5E2-22_____using substitution.
x%5E2-4x%2B1-22=0
x%5E2-4x-21=0___________AND THAT IS FACTORABLE.