SOLUTION: Write a equation in standard form for the line that passes through the point (-3,7) and has a slope of -4/5 S0 FAR I HAVE THIS BUT THEN I GET STUCK! I PUT IT IN POINT SLOPE FO

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Write a equation in standard form for the line that passes through the point (-3,7) and has a slope of -4/5 S0 FAR I HAVE THIS BUT THEN I GET STUCK! I PUT IT IN POINT SLOPE FO      Log On


   

Question 75677: Write a equation in standard form for the line that passes through the point (-3,7) and has a slope of -4/5
S0 FAR I HAVE THIS BUT THEN I GET STUCK!
I PUT IT IN POINT SLOPE FORM:y--3=-4/5[x-7]
THEN i get stuck there

CAN y0U PL3AS3 H3Lp M3?!!?!?
PLEASE && THANK y0U!!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
y-y%5B1%5D=m%28x-x%5B1%5D%29
y-y%5B1%5D=m%28x-x%5B1%5D%29 Plug in the given slope and the point (you're on the right track but you mixed up your x and y point)
y-7=%284%2F5%29%28x-%28-3%29%29
y-7=%284%2F5%29%28x%2B3%29
y-7=%284%2F5%29x%2B%284%2F5%29%283%29%29 Distribute the (4/5)
y-7=%284%2F5%29x%2B12%2F5 Multiply
y=%284%2F5%29x%2B12%2F5%2B7 Add 7 to both sides
y=%284%2F5%29x%2B12%2F5%2B35%2F5
y=%284%2F5%29x%2B47%2F5
y-%284%2F5%29x=47%2F5Subtract %284%2F5%29x from both sides
5%28y-%284%2F5%29x%29=cross%285%29%2847%2Fcross%285%29%29 Multiply both sides by the LCD (which is 5) to clear the denominators
5y-4x=47
So the equation in standard form is:
-4x%2B5y=47
Where A=-4, B=5,C=47
If you want A>0 then it equals:
4x-5y=-47
Where A=4, B=-5,C=-47