Question 71736This question is from textbook Saxon Algebra 1
: Use elimination to solve:
x+3y=16
2x-y=4
How do I find what x or y is equal to?
This question is from textbook Saxon Algebra 1
Answer by funmath(2933)   (Show Source):
You can put this solution on YOUR website! Use elimination to solve:
L1 x+3y=16
L2 2x-y=4
Multiply L2 by 3 so that when you add L1+L2 the y's cancel so that you can solve for x.
L2 3(2x-y)=3(4) ---> 6x-3y=12
Now add this to L1:
x+3y=16
6x-3y=12
_________
7x+0=28
7x=28
7x/7=28/7
x=4
Now substitute 4 in for x in either L1 or L2 and solve for y, I'm going with L1:
(4)+3y=16
4+3y=16
4-4+3y=16-4
3y=12
3y/3=12/3
y=4
The solution (x,y) is (4,4)
Happy Calculating!!!
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