SOLUTION: write the slope intercept form for an equation of the line perpendicular to the graph of the given equation and passing through the given point? 2x-7y=1

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Question 71084This question is from textbook
: write the slope intercept form for an equation of the line perpendicular to the graph of the given equation and passing through the given point?
2x-7y=1, (-4,0)
 This question is from textbook

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
2x-7y=1
-7y=-2x+1
y=-2x/-7+1/-7
y=2x/7-1/7 the given line has a slope of 2/7.
therefore the perpendicular lines slope is the negative reciprical (-7/2)
now replace the x & y values in the line equation y=mx+b with (-4,0) & sole for the y intercept (b)
0=-7/2*-4+b
0=28/2+b
b=-28/2
b=-14 thus the equation of the perpendicular line is
y=-7x/2-14
here are the two libnes plotted
+graph%28+300%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+y+=+2x%2F7+-1%2F7%2C+y+=+-7x%2F2+-14%29+ (graph 300x200 pixels, x from -5 to 5, y from -5 to 5, of TWO functions y = 2x/7 -1/7 and y = -7x/2 -14).