SOLUTION: Suppose that the length of a rectangle is 3 in longer than the width and the perimeter ofathe rectangle is 78. a. Set up an equatio involving only w, the width of the rectangle

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Question 709245: Suppose that the length of a rectangle is 3 in longer than the width and the perimeter ofathe rectangle is 78.
a. Set up an equatio involving only w, the width of the rectangle
b. Solve linear equation algebraically to find the width of the rectangle. Find the length as well.
c. Using the the same length you have as you answer and part b find a new perimeter if the new width is 4 more than one third of the length.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x is length. w is width.

x=w%2B3
AND
2%28x%2Bw%29=78

FINDING w, WIDTH
highlight%282%28%28w%2B3%29%2Bw%29=78%29
4w+6=78
w=72/4
w=18

FINDING x, LENGTH
x=w+3
x=18+3
x=21

Summary of dimensions
highlight%28x=21%29, highlight%28w=18%29