Question 70587This question is from textbook Intermediate Algerba
: (3,_),(_,-1),2x-3y=5
This question is from textbook Intermediate Algerba
Answer by bucky(2189)   (Show Source):
You can put this solution on YOUR website! (3,_),(_,-1),2x-3y=5
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This is two separate problems. The first problem is that you are given (3,_) and the equation
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2x - 3y = 5
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The 3 in (3,___) represents x. Substitute 3 for x in the equation and solve for y:
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2(3) - 3y = 5
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Multiply out the left side to get:
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6 - 3y = 5
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Subtract 6 from both sides:
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-3y = -1
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Divide both sides by -3 to end up with:
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y = (-1/-3) = 1/3
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So the missing entry in (3,_) is 1/3 and the answer becomes (3, 1/3)
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The second problem involves the answer set (_, -1) for the equation 2x - 3y = 5. Substitute
-1 for y in the equation to get:
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2x - 3(-1) = 5
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And multiply out to get:
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2x + 3 = 5
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Subtract 3 from both sides:
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2x = 2
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Divide both sides by 2 and the result is:
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x = 1
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So the missing x value in (_, -1) is 1 and the answer set is (1, -1)
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Hope this helps you to understand what the problem was looking for.
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