SOLUTION: A room is 1.5 times long as it is wide and its perimeter is 25 meters. find the dimension of the room?

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: A room is 1.5 times long as it is wide and its perimeter is 25 meters. find the dimension of the room?      Log On


   



Question 70282: A room is 1.5 times long as it is wide and its perimeter is 25 meters. find the dimension of the room?
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Two equations are required.
You know that the perimeter of a rectangle is given by adding a length, a width, another length,
and another width to get the perimeter.
Let L represent the Length, W represent the Width, and P represent the Perimeter of the
rectangle. With this notation, the equation for the perimeter of the rectangle is:
.
P+=+L+%2B+W+%2B+L+%2B+W
.
This simplifies to:
.
P+=+2%2AL+%2B+2%2AW
.
The problem gives the perimeter as 25 meters. Substitute this:
.
25+=+2%2AL+%2B+2%2AW
.
The problem also says that the length is 1.5 times the width. In equation form, this is:
.
L+=+1.5%2AW
.
Substitute this in place of L in the perimeter equation:
.
25+=+2%2A1.5%2AW+%2B+2%2AW
.
Multiply out the first term on the right side:
.
25+=+3%2AW+%2B+2%2AW
.
and combine the two terms on the right side to get:
.
25+=+5%2AW
.
Divide both sides by 5 and you find that
.
W+=+5+meters
.
And since the length is 1.5 times as long, the length is:
.
L+=+1.5%2A5+=+7.5+meters
.
Check it.
P+=+7.5+%2B+5+%2B+7.5+%2B+5+=+25+meters
.
The answer checks.
.
Hope this helps you to understand the problem.