Question 693720: David has been working for his company since 1990. Each year he gets a $2100 raise, in 1998 he earned one and a half times as much as he earned in 1990.
Write an equation in the form of y=mx+b that models David's salary y in terms of number of years x since he started working there. What was his salary in 1998? How much will he earn in 2005?
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! David has been working for his company since 1990. Each year he gets a $2100 raise, in 1998 he earned one and a half times as much as he earned in 1990.
Write an equation in the form of y=mx+b that models David's salary y in terms of number of years x since he started working there. What was his salary in 1998? How much will he earn in 2005?
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Let his salary in 1990 be "y" ; Then his slary in 1998 is (3/2)y.
Form: y = mx + b
m = 2100 because slope is the change in y when x increases by 1.
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Using (0,y)
y = 2100x + b
y = b (the 1st years salary)
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Using (8,(3/2)b)
(3/2)b = 2100(8) + b
(1/2)b = 2100*8
b = 2100*16
$33,600 (1st year salary)
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Equation:
y = 2100x + 33,600
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Salary in 1998:
f(8) = 2100*8 + 33,600 = $50,400
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Salary in 2005
f(5) = 2100*5 + 33,600 = $44,100
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Cheers,
Stan H.
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Answer by josmiceli(19441)  (Show Source):
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