SOLUTION: the perimeter of a rectangle is 48 inches.The length is 6 inches greater than the width.Define the variables,and write equaations to represent this situation.solve the system by su
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Question 681983: the perimeter of a rectangle is 48 inches.The length is 6 inches greater than the width.Define the variables,and write equaations to represent this situation.solve the system by substitution Answer by tsewaitung(11) (Show Source):
You can put this solution on YOUR website! let the length be x and the width be y.
from the question, we have
2(x+y)=48
x=y+6
by substituting the second equaation into the first equaation, we have
2[(y+6)+y)=48
2[y+6+y]=48
2[2y+6]=48
4[y+3]=48
y+3=12
by substituting y=9 into the second equaation, we have
x=9+6
the length of the rectangle is 15 inches and the width of the rectangle is 9 inches.
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