SOLUTION: find an equation of the line L, where L is perpendicular to y=5/2x and passes through the point (2,5)

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Question 678534: find an equation of the line L, where L is perpendicular to y=5/2x and passes through the point (2,5)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

y = mx + b

y = -2/5x + b (flip the fraction and the sign to go from 5/2 to -2/5)

5 = (-2/5)(2) + b

5 = -4/5 + b

5 + 4/5 = b

25/5 + 4/5 = b

29/5 = b

b = 29/5

So m+=+-2%2F5 and b+=+29%2F5 which means the equation is y+=+%28-2%2F5%29x%2B29%2F5