SOLUTION: I try doing but I got stuck on the last part. How do you solve ((3x^2)(6x^-1)^2/(16y^3)(5y^-1)). I got 108x^0/80y^2 but you have to simplify it which is 27/20y^2 but I do not under
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-> SOLUTION: I try doing but I got stuck on the last part. How do you solve ((3x^2)(6x^-1)^2/(16y^3)(5y^-1)). I got 108x^0/80y^2 but you have to simplify it which is 27/20y^2 but I do not under
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Question 667884: I try doing but I got stuck on the last part. How do you solve ((3x^2)(6x^-1)^2/(16y^3)(5y^-1)). I got 108x^0/80y^2 but you have to simplify it which is 27/20y^2 but I do not understand how they got the 27 from. Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website! I try doing but I got stuck on the last part. How do you solve ((3x^2)(6x^-1)^2/(16y^3)(5y^-1)). I got 108x^0/80y^2 but you have to simplify it which is 27/20y^2 but I do not understand how they got the 27 from.
You're correct up to this point:
= = 108 * 1 ------ Anything to the "0" power = 1
We now have: , which when simplified results in: --- Dividing numerator and denominator by GCF, 4
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