SOLUTION: I am trying to find the break analysis which I know how to do. I just need to solve for x but right now I have this equation: -2x^2 + 300x = 7200 + 60x How do I get rid of t

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: I am trying to find the break analysis which I know how to do. I just need to solve for x but right now I have this equation: -2x^2 + 300x = 7200 + 60x How do I get rid of t      Log On


   

Question 642310: I am trying to find the break analysis which I know how to do. I just need to solve for x but right now I have this equation:
-2x^2 + 300x = 7200 + 60x
How do I get rid of the exponent -2x^2 so I can have an answer that is
x=?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
-2x%5E2+%2B+300x+=+7200+%2B+60x
-2x%5E2+%2B+300x+-60x-7200=0+
-2x%5E2+%2B+240x+-7200=0+.........each term divide by 2
-x%5E2+%2B+120x+-3600=0+....pull minus out of parenthesizes...note: 120x you can write as 2%2A60 and 3600 as 60%5E2
so, you have
-%28x%5E2+-2%2A60x+%2B60%5E2%29=0+...which is squared difference
-%28x+-60%29%5E2=0+
-%28x+-60%29%28x+-60%29=0+
so, solutions are:-%28x+-60%29=0+...=>...-x+%2B60=0+...=>...60=x+
second solution is same
+graph%28+600%2C+600%2C+-10%2C+85%2C+-40%2C+20%2C-x%5E2+%2B120x+-3600%29+