Question 625047: 1st equation is 4x+3y=26
2nd equatiois y=3x
pls solve this problem. thank you.
Answer by Maths68(1474)   (Show Source):
You can put this solution on YOUR website! 4x+3y=26..........(1)
y=3x..............(2)
Substitute the value of y from (2) to (1)
4x+3(3x)=26
4x+9x=26
13x=26
Divide both sides of above equation by 13
13x/13=26/13
x=2
Now substitute the value of x in (2)
y=3x
y=3(2)
y=6
(x,y)=(2,6)
Check
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Put the value of x and y in (1)
4x+3y=26..........(1)
4(2)+3(6)=26
8+18=26
26=26
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