SOLUTION: 5(3z-1)-3(z+2)=7(z+1) linear equation Help me find the solution Please!!!

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Question 624040: 5(3z-1)-3(z+2)=7(z+1) linear equation Help me find the solution Please!!!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
5%283z-1%29-3%28z%2B2%29=7%28z%2B1%29 Start with the given equation.


15z-5-3z-6=7z%2B7 Distribute.


-11%2B12z=7z%2B7 Combine like terms on the left side.


12z=7z%2B7%2B11 Add 11 to both sides.


12z-7z=7%2B11 Subtract 7z from both sides.


5z=7%2B11 Combine like terms on the left side.


5z=18 Combine like terms on the right side.


z=%2818%29%2F%285%29 Divide both sides by 5 to isolate z.


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Answer:

So the solution is z=18%2F5