SOLUTION: How do I solve this ? A total of 150 tickets were sold for an annual concert to students and non students. Student tickets were $5 and non students were $8. If the total revenue fo

#1...total tickets which is made up of student tickets (s) and non student tickets (n) totals 150. Set up an equationL s+n=150. Solve one in terms of the other: s=150-n.

#2 Student tickets are $5 so the total revenue from student tickets is 5s (5 dollars times the number (s) of student tickets.) Total revenue from non student tickets (n) is 8n. The total revenue was $930 so 5s + 8n = 930.

Substitute the s in terms of n (s=150-n) into that second equation (5s + 8n =930)

5(150-n) + 8n = 930 --> 750 -5n + 8n = 930 ---> 3n = 180 ---> n=60.

s=150-n = 150-60 = 90.

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Hi,  

 A total of 150 tickets were sold for an annual concert to students and non students. 

Student tickets were $5 and thenon students were $8. 

total revenue for the concert was $930

Question states***

 $8x + $5(150-x) = $930    Solve for x 

         3x = 180

          x = 60, the number of $8 tickets.  There were 90 $5 tickets sold

and

 $8*60 + $5*90= $930