SOLUTION: "Arctic Antifreeze" is 18%alchol and "frost No-More" is 10%alchol. How many liters of each should be mixed to get 20L of a mixture that is 15% alchol?

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Question 61079This question is from textbook Intermedidaten Algebra
: "Arctic Antifreeze" is 18%alchol and "frost No-More" is 10%alchol. How many liters of each should be mixed to get 20L of a mixture that is 15% alchol? This question is from textbook Intermedidaten Algebra

Answer by uma(370) (Show Source):
You can put this solution on YOUR website!
Suppose that'x' litres of 18% alcohol is taken.
Then quantity of 10% alcohol needed = (20 - x)litres.[as the total is 20 liters]
Thus the equation becomes
x*0.18 + (20-x)*0.10 = 20*0.15
==> 0.18x + 2 - 0.10x = 3
==> 0.08x + 2 = 3
==> 0.08x + 2 - 2 = 3 - 2
==> 0.08x = 1
==> 0.08x/0.08 = 1/0.08
==> x = 1/0.08
==> x = 12.5
So the quantity of 18% alcohol = 12.5 liters
The quantity of 10% alcohol = 20 - 12.5
= 7.5 liters
Thus 12.5 liters of 18% alcohol is added to 7.5 liters of 10% alcohol to arrive at 20 liters of 15% alcohol.

Good Luck!!!