SOLUTION: the sum of two numbers is 50. Two times the smaller number exceeds the larger number by 31. Find the numbers.

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Question 600129: the sum of two numbers is 50. Two times the smaller number exceeds the larger number by 31. Find the numbers.
Answer by godsgirls(5) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of two numbers is 50. Two times the smaller number exceeds the larger number by 31. Find the numbers.
First we need to write out equations. Let x equal the first number and y equal the second. The sum of two numbers is 50: x+%2B+y+=+50
Two times the smaller number (we'll make that x) exceeds the larger number (y) by 31. 2x+=+y+%2B31
Here I'm going to teach you a trick that will become handy once you get into high school math.
It's called combining equations.
First we need to multiply the first equation by 2.
2%2Ax+%2B+2%2Ay+=+2%2A50 becomes 2x+%2B+2y+=+100
of course, we know from our second equation that 2x = y + 31. So we substitute this into our first equation.
y+%2B+31+%2B+2y+=+100
Combine like terms to get: 3y+%2B+31+=+100
subtract 31 from each side: 3y+%2B+31+-+31+=+100+-+31
Simplify: 3y+=+61
divide both sides by three to isolate y. 3y%2F3+=+61%2F3
this becomes: y+=+23
Now we have y, we can use our first equation to find x.
x+%2B+y+=+50
substitute 23 for y: x+%2B+23+=+50
subtract 23 from each side. x+%2B+23+-+23+=+50+-+23
simplify: x+=+27
So your two numbers are 27 and 23. I hope this helps you!