SOLUTION: Solve this system of linear equations: {{{y=x-2}}} {{{2x+2y=4}}}

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Question 595485: Solve this system of linear equations:
y=x-2
2x%2B2y=4
Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, there--
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I'll solve this using the substitution method. Since y is equal to x-2, we will substitute x-2 for y in the second equation.
2x%2B2y=4
2x%2B2%28x-2%29=4
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Now simplify and solve for x.
2x%2B2x-4%29=4
4x-4=4
4x=8
x=2
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Substitute 2 for x in either equation and solve for y.
y=x-2
y=2-2
y=0
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We have x-2 and y=0. Check your work by substituting these values into both equations.
y=x-2
0=2-2
0=0
Bingo!
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2x%2B2y=4
2%282%29%2B2%280%29=4
4%2B0=4
4=4
Check!
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The (x,y) ordered pair (2,0) is the solution for this system of equations.
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That's it! Feel free to email me if you have questions about this solution.
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Mrs.Figgy
math.in.the.vortex@gmail.com