SOLUTION: x^2+3=y y=5-x Can someone help me with this i keep getting a negative number !This is substituting Linear quadratic equations.Thanks so much !

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: x^2+3=y y=5-x Can someone help me with this i keep getting a negative number !This is substituting Linear quadratic equations.Thanks so much !      Log On


   

Question 592500: x^2+3=y
y=5-x
Can someone help me with this i keep getting a negative number !This is substituting Linear quadratic equations.Thanks so much !
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+3=y
y=5-x
So x^2+3 = 5-x
x^2+x-2=0
(x+2)(x-1)=0
x=-2 OR x=1