SOLUTION: Hi, the question I have is
a manufacturer of tv dinners has monthly revenue of R= -q^2+25q
R is revenue in hundreds of dollars when q dinners are produced.
Cost function is C=4q
Algebra ->
Coordinate Systems and Linear Equations
-> Lessons
-> SOLUTION: Hi, the question I have is
a manufacturer of tv dinners has monthly revenue of R= -q^2+25q
R is revenue in hundreds of dollars when q dinners are produced.
Cost function is C=4q
Log On
Question 55056: Hi, the question I have is
a manufacturer of tv dinners has monthly revenue of R= -q^2+25q
R is revenue in hundreds of dollars when q dinners are produced.
Cost function is C=4q+40 where C is also in hundreds of dollars.
Manufacturer is limited to producing 2500 dinners per month.
Solve the equations and use a graph to show how manufacturer can operate a profit.
To solve the equations would I have 2500= (-q^2+25q) - (4q+40) since profit is cost-revenue.
So then I have 2500= -q^2 + 25q -4q -40
2500 = -q^2 + 21q -40
2500+40 = -q^2 +21q
2540 = -q^2 +21q
equation to make profit would be -q^2 + 21q - 2540
Then do i find points from this equation to graph it??
I really have no idea and am working with a guess.
Tahnks for any help you could possibly give me!!
You can put this solution on YOUR website! R= -q^2+25q
R is revenue in hundreds of dollars when q dinners are produced.
Cost function is C=4q+40 where C is also in hundreds of dollars.
Manufacturer is limited to producing 2500 dinners per month.
Solve the equations and use a graph to show how manufacturer can operate a profit.
---------
Profit = Revenue - Cost
=(-q^2+25q)-(4q+40)
=-q^+21q-40
--------
To have a profit means -q^2+21q-40>0
To find the solution set you might:
1. graph the parabola or
2. use the quadratic formula
Using the graph method I get 2.11
That is really not a reasonable answer considering
you were told they can produce 2500 meals per month.
But that's the way the math turns out on the problem
as you have posted it.
Cheers,
Stan H.
(