SOLUTION: I'm extremely confused on how to solve a couple of these problems, ex:2x-7y=3 5x-4y=-6 using the elimination method, could you explain a simple way of how to solve? I'm just

Click here to see ALL problems on Linear-systems

Question 543968: I'm extremely confused on how to solve a couple of these problems,
ex:2x-7y=3
5x-4y=-6
using the elimination method, could you explain a simple way of how to solve? I'm just extremely lost and any help would be greatly appreciated.
thank you, Lexy.
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
2x - 7y = 3
5x - 4y =-6
:
In the elimination method we multiply one or both equations with values that will
make the coefficient of one of the variables the same but with with different signs
:
In the above system, we can multiply the 1st equation by -5 and the 2nd equation by 2, resulting in:
-10x + 35y = -15
+10x - 8y = -12
-----------------adding eliminates x, find y
27y = -27
y =
y = -1
:
Use the 1st original equation to find x, replace y with -1
2x - 7(-1) = 3
2x + 7 = 3
2x = 3 - 7
2x = -4
x =
x = -2
:
Use the 2nd equation to check our solutions of x=-2 and y=-1
5x - 4y =-6
5(-2) - 4(-1) = -6
-10 + 4 = -6; confirms our solutions
:
:
Has this helped you find your way in the world of eliminations