SOLUTION: solve 3x/5-2/6 =20

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Question 536002: solve 3x/5-2/6 =20
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given to solve for x:
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3x%2F5-2%2F6+=20
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Clear the fractions by multiplying all terms on both sides by (5*6) as follows:
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%285%2A6%2A3x%29%2F5+-+%285%2A6%2A2%29%2F6+=+5%2A6%2A20
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cancel the denominators with the same value in the corresponding numerator:
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as a result of this procedure the equation becomes:
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6%2A3x+-+5%2A2+=+5%2A6%2A20
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do the multiplications in each term and the result is:
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18x+-+10+=+600
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get rid of the -10 on the left side by adding 10 to both sides. On the left side of the equation the -10 and the +10 cancel each other. On the right side this just adds 10 to 600. The equation is then:
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18x+=+610
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Solve for x by dividing both sides by 18. The result is:
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x+=+610%2F18
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Do the division of 18 into 610 and you get the answer:
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x+=+33.8888889
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Hope this helps you to understand one way of clearing the fractions in an equation so that you can work the problem using integers.
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