SOLUTION: the length of a rectangle is 20ft. less than twice the width. of the perimeter of the rectangle is 260ft. find the length and width of the rectangle

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Question 528732: the length of a rectangle is 20ft. less than twice the width. of the perimeter of the rectangle is 260ft. find the length and width of the rectangle
Answer by mathstutor494(120) About Me  (Show Source):
You can put this solution on YOUR website!
Let width = x
Then length = 2x-20
Perimeter of the rectangle = 2(Length+Width)
2( 2x-20+x) = 260
2(3x-20) = 260
3x-20= 130
3x = 130+20
x = 150/3 => 50
Therefore Length = 2x-20 => 2*50-20 => 100-20 => 80
Ans : Length 80 ft, Width 50 ft