You can put this solution on YOUR website! the line has a slope of -2/3 and passes through (6,12)
.
Plug into "point-slope" form:
y - y1 = m(x - x1)
y - 12 = (-2/3)(x - 6)
y - 12 = (-2/3)x + 4
y = (-2/3)x + 16 (this is what they're asking for... in "slope-intercept")
You can put this solution on YOUR website! Given the line has slope -2/3 we can define the equation using slope-intercept form:
.
y = -2/3x + b
.
Use the point to find 'b'.
.
12 = -(2/3)*6 + b
12 = -4 + b
16 = b
.
So the equation is:
.
y = -2/3x + 16
.
(