Question 475726: what is the equation in point-slope form of the line perpendicular to 3x+6y=5 and through the point (1,3).
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! what is the equation in point-slope form of the line perpendicular to 3x+6y=5 and through the point (1,3).
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Solve for "y":
y = (-1/2)x + (5/6)
slope is -1/2
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Slope of all perpendicular must be 2
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Equation Form:
y = mx + b
Using (1,3) and m = 2 solve for "b:
3 = 2*1 + b
b = 1
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Equation:
y = 2x + 1
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Cheers,
Stan H.
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