SOLUTION: Solve: x+b/2y=-b^2/4 x-y=-1 where b does not equal to -2 I changed x-y=-1 to y=1+x then; x+b/2(1+x)=-b^2/4 x+b/2+b/2X=b^2/4 x+b/2x=b^2/4-b/2 that

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Solve: x+b/2y=-b^2/4 x-y=-1 where b does not equal to -2 I changed x-y=-1 to y=1+x then; x+b/2(1+x)=-b^2/4 x+b/2+b/2X=b^2/4 x+b/2x=b^2/4-b/2 that      Log On


   



Question 464227: Solve:
x+b/2y=-b^2/4
x-y=-1 where b does not equal to -2
I changed x-y=-1 to y=1+x
then; x+b/2(1+x)=-b^2/4
x+b/2+b/2X=b^2/4
x+b/2x=b^2/4-b/2
thats all I can do...


Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x+b/2y=-b^2/4
x-y=-1 where b does not equal to -2
I changed x-y=-1 to y=1+x
then; x+b/2(1+x)=-b^2/4
x + b = (-b^2/4)*2(1+x) = -b^2/2 - b^2x/2
x + b^2x/2 = -b - b^2/2
x(1 + b^2/2) = -b - b^2/2
x+=+-%28b+%2B+b%5E2%2F2%29%2F%281+%2B+b%5E2%2F2%29
x+=+-%282b+%2B+b%5E2%29%2F%282+%2B+b%5E2%29
===================================
y = x+1
y+=+%28-2b+-+b%5E2+%2B+2+%2B+b%5E2%29%2F%282+%2B+b%5E2%29
y+=+%28-2b+%2B+2%29%2F%282+%2B+b%5E2%29