SOLUTION: determin the equasion of a line tha passes through (6,18) and (-12,3)
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Question 463586
:
determin the equasion of a line tha passes through (6,18) and (-12,3)
Answer by
rfer(16322)
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m=(3-18)/(-12-6)
m=-15/-18
m=5/6
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y=mx+b
3=5/6*-12+b
3=-10+b
b=-13
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y=5/6x-13