SOLUTION: An Investment is worth $ 3432 in 1991. By 1995 it as grown to $ 4132. Let y be the value of the investment in the year x, where x = 0 represents 1991. Write a linear equation that
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-> SOLUTION: An Investment is worth $ 3432 in 1991. By 1995 it as grown to $ 4132. Let y be the value of the investment in the year x, where x = 0 represents 1991. Write a linear equation that
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Question 46104: An Investment is worth $ 3432 in 1991. By 1995 it as grown to $ 4132. Let y be the value of the investment in the year x, where x = 0 represents 1991. Write a linear equation that models the value of the investment in the year x.
I am to solve and assume that the exercise describes a linear relationship. Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! P(0,3432) and P(4,4132)
M = (y2 - y1)/(x2 - x1) = (4132 - 3432)/(4 - 0) = (700)/4 = 175
Point-Slope Form:
(