SOLUTION: solve elimination/addtion method 2c - 3d = 14 5c - 6d = 32 show steps

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Question 449438: solve elimination/addtion method
2c - 3d = 14
5c - 6d = 32
show steps
Answer by mananth(16946) About Me  (Show Source):
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2c-3d=14 .............1
5c-6d=32 .............2
Eliminate y
multiply (1)by-2
Multiply (2) by 1
-4c+6d= -28
5c-6d=32
Add the two equations
c=4
plug value of c in (1)
2c-3d=14
8-3d=14
-3d=14 -8
-3d=6
d=-2