Question 445734: I tried this on my own and then checked it against answers I found and nothing makes sense to me now...this is a 4 part problem and I am showing what I got so far too.
Imagine you are in the market for a new home and are interested in a new housing community under construction in a different city.
a-The sales rep informs you that there are 56 houses for sale with two floor plans still available. Use x to represent floor plan one and y to represent floor plan two. Write an equation that illustrates the situation. I wrote x+y=56
b-The sales rep later indicates that there are three times as many homes available with the second floor plan than the first. Write an equation that illustrates this situation. Use the same variables you used in part a. I got y=3(x)
c-Use the equations from parts a and b of this exercise as a system of equations. Use substitution to determine how many of each type of floor plan is available. Describe the steps you used to solve the problem. so my equations are x+y=56 and y=3(x)...is this all right so far?
d-What are the intercepts of the equation from part a of this problem? What are the intercepts from part b of this problem? Where would the lines intersect if you solved the system by graphing? I got two intercepts of (0,56) and (56,0). I also found that (14,42) is where it intercepts. Am I right or can you show me the correct way? I tried the equations the best I could....
Answer by scott8148(6628)   (Show Source):
You can put this solution on YOUR website! a), b) and d) look good
for c), substitute the equivalent value of y into your 1st equation ___ x + (3x) = 56 ___ 4x = 56 ___ x = 14
___ then substitute the value of x into your 2nd equation ___ y = 3(14) = 42
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