SOLUTION: I have to show my work and I only know how to do these on a calculator any help would be greatly appreciated!! -5x - 4y + 12z = -140 9x - 8y + z = -649 3x - 2y + 6z = -290

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: I have to show my work and I only know how to do these on a calculator any help would be greatly appreciated!! -5x - 4y + 12z = -140 9x - 8y + z = -649 3x - 2y + 6z = -290      Log On


   



Question 429957: I have to show my work and I only know how to do these on a calculator any help would be greatly appreciated!!
-5x - 4y + 12z = -140
9x - 8y + z = -649
3x - 2y + 6z = -290

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
-5x - 4y + 12z = -140
9x - 8y + z = -649
3x - 2y + 6z = -290
Solved by pluggable solver: Using Cramer's Rule to Solve Systems with 3 variables







First let A=%28matrix%283%2C3%2C-5%2C-4%2C12%2C9%2C-8%2C1%2C3%2C-2%2C6%29%29. This is the matrix formed by the coefficients of the given system of equations.


Take note that the right hand values of the system are -140, -649, and -290 and they are highlighted here:




These values are important as they will be used to replace the columns of the matrix A.




Now let's calculate the the determinant of the matrix A to get abs%28A%29=506. To save space, I'm not showing the calculations for the determinant. However, if you need help with calculating the determinant of the matrix A, check out this solver.



Notation note: abs%28A%29 denotes the determinant of the matrix A.



---------------------------------------------------------



Now replace the first column of A (that corresponds to the variable 'x') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bx%5D (since we're replacing the 'x' column so to speak).






Now compute the determinant of A%5Bx%5D to get abs%28A%5Bx%5D%29=-20240. Again, as a space saver, I didn't include the calculations of the determinant. Check out this solver to see how to find this determinant.



To find the first solution, simply divide the determinant of A%5Bx%5D by the determinant of A to get: x=%28abs%28A%5Bx%5D%29%29%2F%28abs%28A%29%29=%28-20240%29%2F%28506%29=-40



So the first solution is x=-40




---------------------------------------------------------


We'll follow the same basic idea to find the other two solutions. Let's reset by letting A=%28matrix%283%2C3%2C-5%2C-4%2C12%2C9%2C-8%2C1%2C3%2C-2%2C6%29%29 again (this is the coefficient matrix).




Now replace the second column of A (that corresponds to the variable 'y') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5By%5D (since we're replacing the 'y' column in a way).






Now compute the determinant of A%5By%5D to get abs%28A%5By%5D%29=17204.



To find the second solution, divide the determinant of A%5By%5D by the determinant of A to get: y=%28abs%28A%5By%5D%29%29%2F%28abs%28A%29%29=%2817204%29%2F%28506%29=34



So the second solution is y=34




---------------------------------------------------------





Let's reset again by letting A=%28matrix%283%2C3%2C-5%2C-4%2C12%2C9%2C-8%2C1%2C3%2C-2%2C6%29%29 which is the coefficient matrix.



Replace the third column of A (that corresponds to the variable 'z') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bz%5D






Now compute the determinant of A%5Bz%5D to get abs%28A%5Bz%5D%29=-8602.



To find the third solution, divide the determinant of A%5Bz%5D by the determinant of A to get: z=%28abs%28A%5Bz%5D%29%29%2F%28abs%28A%29%29=%28-8602%29%2F%28506%29=-17



So the third solution is z=-17




====================================================================================

Final Answer:




So the three solutions are x=-40, y=34, and z=-17 giving the ordered triple (-40, 34, -17)




Note: there is a lot of work that is hidden in finding the determinants. Take a look at this 3x3 Determinant Solver to see how to get each determinant.