SOLUTION: piece of wire 42 cm long is bent into a rectangle whose length is twice its width. Find the dimensions of the rectangle.

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Question 429904: piece of wire 42 cm long is bent into a rectangle whose length is twice its width. Find the dimensions of the rectangle.
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of the rectangle = 2l + 2w
Given: l = 2w
So we can write the following equation:
2(2w) + 2w = 42
Solve for w:
6w = 42 -> w = 7
So the length = 2w = 2(7) = 14
Ans: length = 14, width = 7