SOLUTION: How do you solve 2x+3y=1 and -3x+y=15 by substitution? I have tried solving for the x and the y in the first probem but i getr frarctions and i dont think they are right..

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: How do you solve 2x+3y=1 and -3x+y=15 by substitution? I have tried solving for the x and the y in the first probem but i getr frarctions and i dont think they are right..      Log On


   

Question 405663: How do you solve 2x+3y=1 and -3x+y=15 by substitution?
I have tried solving for the x and the y in the first probem but i getr frarctions and i dont think they are right..
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

2x%2B3y=1 and -3x%2By=15.......... by substitution

Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++2%5Cx+%2B+3%5Cy+=+1%2C%0D%0A++++-3%5Cx+%2B+1%5Cy+=+15+%29%0D%0A++We'll use substitution. After moving 3*y to the right, we get:
2%2Ax+=+1+-+3%2Ay, or x+=+1%2F2+-+3%2Ay%2F2. Substitute that
into another equation:
-3%2A%281%2F2+-+3%2Ay%2F2%29+%2B+1%5Cy+=+15 and simplify: So, we know that y=3. Since x+=+1%2F2+-+3%2Ay%2F2, x=-4.

Answer: system%28+x=-4%2C+y=3+%29.