Question 388866: perform the indicated operations:
[1 1 -3] [-2 -1 8]
3 [3 2 3]+4[4 2 2]
[7 -1 6] [3 6 3]
solve the minimization problem:
minimize C= -2+y
subject to 3x+4y < 6
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3x+2y < 12
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x>0, y > 0
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Answer by haileytucki(390)   (Show Source):
You can put this solution on YOUR website! Re these seperate??
If not you have the option of finding the GFC, LCD, or LCM
The GFC:
[11-3][-2-18]_3[323]+4[422]_[7-16][363]
Subtract 3 from 11 to get 8.
[8][-2-18]+3[323]+4[422]+[7-16][363]
Subtract 18 from -2 to get -20.
[8][-20]+3[323]+4[422]+[7-16][363]
Subtract 16 from 7 to get -9.
[8][-20]+3[323]+4[422]+[-9][363]
Multiply 8 by -20 to get -160.
[-160]+3[323]+4[422]+[-9][363]
Multiply 3 by each term inside the parentheses.
[-160]+969+4[422]+[-9][363]
Multiply 4 by each term inside the parentheses.
[-160]+969+1688+[-9][363]
Multiply -9 by 363 to get -3267.
[-160]+969+1688+[-3267]
Remove the parentheses that are not needed from the expression.
-160+969+1688-3267
Add 969 to -160 to get 809.
809+1688-3267
Add 1688 to 809 to get 2497.
2497-3267
Subtract 3267 from 2497 to get -770.
Answer: -770
The LCD
[11-3][-2-18]_3[323]+4[422]_[7-16][363]
Since there are no fractions, and therefore no denominators, the least common denominator is 1. Since this has no fractions, try to find the LCM of this set of expressions.
1
The LCM
[11-3][-2-18]_3[323]+4[422]_[7-16][363]
The LCM of [11-3][-2-18],3[323]+4[422],[7-16][363] is 12[-2-18][11-3][422][363][7-16][323].
Answer: 12[-2-18][11-3][422][363][7-16][323]
Please specify more in your second question.
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