Question 377513: suppose that y varies directly as the sqaure root of x, and that y=32 when x=16. What is y when x=50? Found 2 solutions by mananth, ewatrrr:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! suppose that y varies directly as the sqaure root of x, and that y=32 when x=16. What is y when x=50?
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x=16,y=32
plug the value
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32=4k
/4
k=32/4
k=8
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x=50, k= 8
y =56.56
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m.ananth@hotmail.ca
Hi
*Note: When Quantities vary directly,they are related by the relationship:
In general: k being the constant of proportionality.
y varies directly as the square root of x
y=32 when x=16
32 = k*4
8 = k
What is y when x=50
