Question 369116: How do you solve a problem like this? y= 3x and 3x+4y= 30
Answer by neatmath(302)   (Show Source):
You can put this solution on YOUR website! The easiest way is by substitution.
y=3x
3x+4y=30
Since we know what y equals in the first equation (3x), we will substitute that in for the value of y in the second equation.
So we now have
3x+4*(3x)=30
3x+12x=30
15x=30
x=2
Since we know what x has to be, we can just substitute that value into either equation to find the value of y.
y=3x
y=3*2
y=6
The solution to this system of equations is x=2 and y=6, or the point (6,2)
When dealing with a system of 2 linear equations, the solution to the system will always be a singe point, unless the two lines are parallel or are actually the same line. :)
I hope this helps!
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