SOLUTION: write the equation of the line passing through the point (-3,1) which is perpendicular to line 7y-5x-7=0

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Question 349014: write the equation of the line passing through the point (-3,1) which is perpendicular to line 7y-5x-7=0
Found 2 solutions by mananth, solver91311:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
(-3,1) which is perpendicular to line 7y-5x-7=0
.
7y-5x-7=0
7y=5x+7
/7
y= 5x/7 +1
slope = 5/7
...
The slope of line perpendicular to this line will be -7/5
point ( -3,1)
Plug value of a,y & m to get value of b
in y= mx+b
1=-7/5 * -3 +b
1=21/5 +b
1-21/5 = b
-16/5 =b
The equation will be
y= -7/5 x -16/5
graph%28500%2C500%2C-20%2C20%2C-20%2C20%2C%28%28-7x%2F5%29-%2816%2F5%29%29%29

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Calculate the slope of the given line, take the opposite of the coefficient on divided by the coefficient on

Calculate the slope of the desired line by taking the negative reciprocal of the given line. Because:



Use the point-slope form of an equation of a line:



where are the coordinates of the given point and is the calculated slope.


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