Question 328024: The perimeter of a rectangle is 196 inches. The length exceeds the width by 44 inches. Find the length and width???
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Let x = width
x+44 = length
2W + 2 L = P
2(x)+2(x+44)=196
2x+2x +88=196
4x=196-88
4x=108
x=27 width
x+44=27+44=71 length
Check:
2*27+2*71
54+142
196
It checks!!
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