Please help me solve this problem:
The solution of the system 4x+5y=2 and 6x-2y=b is (3,a).
What are the values of a and b?
Since (3,a) is their common solution, it is a solution to both
equations. So we substitute " 3 " for x and " a " for y in the
first one:
4x + 5y = 2
4(3) + 5(a) = 2
12 + 5a = 2
5a = -10
a = -2
Now we substitute " 3 " for x and " a " for y in the second one:
6x - 2y = b
6(3) - 2(a) = b
18 - 2a = b
But since we have already found " a " to be -2, we substitute -2
for " a " and get
18 - 2(-2) = b
18 + 4 = b
22 = b
Edwin
AnlytcPhil@aol.com
