SOLUTION: please solve for x and y.
mixture problem.
1.a chemist want to make 75 liters of 16% acid solution.he is going to make it by mixing a 10% acid and a 25% acid solution.how man
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mixture problem.
1.a chemist want to make 75 liters of 16% acid solution.he is going to make it by mixing a 10% acid and a 25% acid solution.how man
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Question 266438: please solve for x and y.
mixture problem.
1.a chemist want to make 75 liters of 16% acid solution.he is going to make it by mixing a 10% acid and a 25% acid solution.how many liters of each will he need?
please answer this problem right away.I NEED YOUR HELP
You can put this solution on YOUR website! solve for x and y.
mixture problem.
:
1.a chemist want to make 75 liters of 16% acid solution.
x + y = 75
y = (75-x); this form for substitution
:
he is going to make it by mixing a 10% acid and a 25% acid solution.
an amt of acid equation
.10x + .25y = .16(75)
Replace y with (75-x)
.10x + .25(75 - x) = .16(75)
.10x + 18.75 - .25x = 12
.10x - .25x = 12 - 18.75
-.15x = -6.75
.15x = 6.75
x =
x = 45 liter of 10% acid
then
y = 75 - 45 = 30 liters of 25%
:
:
Check in the original equation:
.10(45) + .25(30) = .16(75)
4.5 + 7.5 = 12
