Question 265448: Please help me solve this system of equations:
36x-15y+50z=-10
2x+25y=40
54x-5y+30z=-160
Thank you so much! Found 2 solutions by vksarvepalli, palanisamy:Answer by vksarvepalli(154) (Show Source):
You can put this solution on YOUR website! 36x-15y+50z=-10 ----------------------- 1
2x+25y=40 ----------------------- 2
54x-5y+30z=-160 ----------------------- 3
multiply eq. 1 by 3 and eq. 3 by 5 and then subtract both (to eliminate z)
so we get 108x-45y+150z=-30
270x-25y+150z=-800
-162x-20y=770
now multiply eq.2 by 81 and add to the above eq.
we get 2005y=4010
so y=2
from eq. 2
2x+50=40 => 2x=-10
=> x=-5
from eq.1 -180-30+50z=-10
so 50z=200
=> z=4
so x=-5, y=2, z=4
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