SOLUTION: Here is another problem that I am confused with. Some of the problems are one way and then they are changed around and that when I get lost. y = 2x + 1 x + y = 4

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Here is another problem that I am confused with. Some of the problems are one way and then they are changed around and that when I get lost. y = 2x + 1 x + y = 4      Log On


   

Question 264736: Here is another problem that I am confused with. Some of the problems are one way and then they are changed around and that when I get lost.
y = 2x + 1
x + y = 4
Found 2 solutions by jim_thompson5910, mananth:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x+%2B+y+=+4 Start with the second equation.


x+%2B+2x%2B1+=+4 Plug in y+=+2x+%2B+1


3x%2B1=4 Combine like terms on the left side.


3x=4-1 Subtract 1 from both sides.


3x=3 Combine like terms on the right side.


x=%283%29%2F%283%29 Divide both sides by 3 to isolate x.


x=1 Reduce.


y+=+2x+%2B+1 Move back to the first equation.


y+=+2%281%29+%2B+1 Plug in x=1


y+=+2+%2B+1 Multiply


y+=+3 Add


So the solutions are x=1 and y+=+3 which form the ordered pair (1,3)


This means that the system is consistent and independent.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Here is another problem that I am confused with. Some of the problems are one way and then they are changed around and that when I get lost.
y = 2x + 1
x + y = 4
whenever you get such a problem first you get all the variables on the left side of the equation and the numbers on the right side.
y-2x=1
y+x=4
subtract
-3x=-3
3x=3
x=1
y+1=4
y=4-1 =3