SOLUTION: I am trying to find out two symmetrical points from the equation y= -1/3(x-5)^2 -8 the vertex is 5,-8 and the symmetry axis is x=5 the parabola is concave down as -1/3 is
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Question 252576: I am trying to find out two symmetrical points from the equation y= -1/3(x-5)^2 -8 the vertex is 5,-8 and the symmetry axis is x=5 the parabola is concave down as -1/3 is a negative. I am sruggling to find the two points so i can do a graph. Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website! I am trying to find out two symmetrical points from the equation y= -1/3(x-5)^2 -8 the vertex is 5,-8 and the symmetry axis is x=5 the parabola is concave down as -1/3 is a negative. I am sruggling to find the two points so i can do a graph.
(-1,-20) and (11,-20 are symmetrical points
(2,-11) and (8,-11) are symmetrical points
Edwin
