You can put this solution on YOUR website! X + y = 5
X + 2z = 6
Y + 3z = 4
:
Rewrite it like this
x + y + 0z = 5
x + 0y + 2z = 6
0x + y + 3z = 4
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Subtract the 3rd equation from the 1st equation
x + y + 0z = 5
0x + y + 3z = 4
--------------------subtraction eliminates y
x - 3z = 1
x = 3z + 1
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Substitute (3z+1) for x in the 2nd equation
3z + 1 + 2z = 6
5z = 6 - 1
5z = 5
z = 1
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Find x using x = 3z + 1
x = 3(1) + 1
x = 4
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Find y using the 1st equation: x + y = 5
4 + y = 5
y = 5-4
y = 1
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I'll let you check these values in the original equations