SOLUTION: Find the equation of the line that satisfies the given condition. The line passing through the origin and parallel to the line passing through the points (-5, -6) and (1, -2)

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Find the equation of the line that satisfies the given condition. The line passing through the origin and parallel to the line passing through the points (-5, -6) and (1, -2)       Log On


   

Question 222604: Find the equation of the line that satisfies the given condition.
The line passing through the origin and parallel to the line passing through the points (-5, -6) and (1, -2)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The line passing through the origin and parallel to the line passing through the points (-5, -6) and (1, -2)
:
Find the slope of the line that passes thru these points (parallel lines have the same slope)
m = %28-2+-+%28-6%29%29%2F%281+-+%28-5%29%29 = %28-2+%2B+6%29%2F%281+%2B+5%29 + 4%2F6 = 2%2F3
:
Use the point/intercept form, y = mx + b: line passes thru origin so b = 0
y = 2%2F3x + 0
or just
y =2%2F3x