Question 215585: what is the y intercept of the points (1, 202) and (4, 382)?
Found 2 solutions by drj, solver91311: Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! What is the y intercept of the points (1, 202) and (4, 382)?
Step 1. We need to find an equation in slope intercept form given as y=mx+b where m is the slope and b is the y-intercept at point (0,b).
Step 2. The slope of the line m is given as
where for our example is x1=1, y1=202, x2=4 and y2=382 (think of ). You can choose the points the other way around but be consistent with the x and y coordinates. You will get the same result.
Step 3. Substituting the above values in the slope equation gives
Step 4. The slope is calculated as 60 or m=60.
Step 5. Now use the slope equation of step 1 and choose one of the given points. I'll choose point (1,202). Letting y=y2 and x=x2 and substituting m=60 in the slope equation given as,
Step 6. Multiply both sides of equation by x-1 to get rid of denomination found on the right side of the equation
Step 7. Now simplify and put the above equation into slope-intercept form.
Add 202 to both sides of the equation
ANSWER in slope-intercept form. m=60 and y-intercept=142
Step 8. See if the other point (4, 382) or x=4 and y=382 satisfies this equation
{{382=382}}} So the point (4,382) satisfies the equation and is on the line. In other words, you can use the other point to check your work.
Note: above equation can be also be transform into standard form as
See graph below to check the above steps.
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc |
Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .- X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 142/-60 = -2.36666666666667.
- Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 142/1 = 142.
- Slope is --60/1 = 60.
- Equation in slope-intercept form: y=60*x+142.
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I hope the above steps were helpful.
And good luck in your studies!
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
Respectfully,
Dr J
Answer by solver91311(24713) (Show Source):
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