SOLUTION: write and solve an Equation for this
at 10 am a car leavesa house at the rate of 60Mi/h. at the same time,another car leaves the same houseat 50 mi/h in the opposite direction.
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at 10 am a car leavesa house at the rate of 60Mi/h. at the same time,another car leaves the same houseat 50 mi/h in the opposite direction.
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Question 214287This question is from textbook
: write and solve an Equation for this
at 10 am a car leavesa house at the rate of 60Mi/h. at the same time,another car leaves the same houseat 50 mi/h in the opposite direction.at what time will the cars be at 330 miles apart? This question is from textbook
You can put this solution on YOUR website! D=RT
330=(60+50)T
330=110T
T=330/110
T=3 HOURS OR 1:00 PM. THEY WILL BE 330 MILES APART.
PROOF:
330=60*3+50*3
330=180+150
330=330
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