SOLUTION: how to solve linear systems algebraically problem: 6x-y=-2 -18x+3y=4

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Question 213899This question is from textbook algebra 2
: how to solve linear systems algebraically
problem: 6x-y=-2
-18x+3y=4 This question is from textbook algebra 2

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
6x-y=-2 or y=6x%2B2
-18x%2B3y=4

Step 1. Let's rewrite the second equation where we can again rearrange by adding 18x to both sides of the equation to yield

3y=18x%2B4

or dividing by 3 to both sides of the equation, we have

y=6x%2B4%2F3

Step 2. Now compare the following equivalent system of equations

y=6x%2B2
y=6x%2B4%2F3

The above equations are in slope intercept form where m=6 for both equations.

Step 3. ANSWER: When the equations of lines have the same slope there is NO SOLUTION since they cannot intersect at a point.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J