SOLUTION: When Mr. Reader packed his books into bundles of 12 books there were 2 books left unpacked. When he repacked his books in bundles of 9, there were 2 books left again. Finally, when

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: When Mr. Reader packed his books into bundles of 12 books there were 2 books left unpacked. When he repacked his books in bundles of 9, there were 2 books left again. Finally, when      Log On


   



Question 209212: When Mr. Reader packed his books into bundles of 12 books there were 2 books left unpacked. When he repacked his books in bundles of 9, there were 2 books left again. Finally, when Mr Reader packed his books in bundles of 7, there were no books left unpacked. Find the smallest number of books that Mr. Reader could have.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Mr. Reader packed his books into bundles of 12 books there were 2 books left unpacked.
When he repacked his books in bundles of 9, there were 2 books left again.
Finally, when Mr Reader packed his books in bundles of 7, there were no books left unpacked.
Find the smallest number of books that Mr. Reader could have.
:
Find a common multiple of 12 & 9; add 2 and see if it is a multiple of 7.
Using this method, I arrived at 180 (started at 108), added 2 to make 182 books
: