SOLUTION: -12xz/(3y)+12z (squared)/x x=-4 y=-2 z=1\2 my answer came out to negative one but my teacher marked that problem as wrong too!i solved the top part which is everything before /x

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: -12xz/(3y)+12z (squared)/x x=-4 y=-2 z=1\2 my answer came out to negative one but my teacher marked that problem as wrong too!i solved the top part which is everything before /x       Log On


   

Question 208616: -12xz/(3y)+12z (squared)/x
x=-4 y=-2 z=1\2
my answer came out to negative one but my teacher marked that problem as wrong too!i solved the top part which is everything before /x in my TI calculator and then divided it by x which equals -4
and still got the answer wrong can you help me???
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
-12xz/(3y)+12z (squared)/x
x=-4 y=-2 z=1\2
----------
-12xz%2F3y+%2B+12z%5E2%2Fx
If that's not what you meant, you need to add parentheses to make it clear.
= -4xz%2Fy+%2B+12z%5E2%2Fx
= (-4*-4*(1/2)/(-2) + 12*(1/4)/(-4)
= 8/(-2) + 3/(-4)
= 16/(-4) + 3/(-4)
= 19/(-4)
= -19/4

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
-12xz/(3y)+12z (squared)/x
x=-4 y=-2 z=1\2
-----------------------------
Substitute:
-12(-4)(1/2)/(3*-2) + 12*(1/2)^2 /(-4)
---
24/(-6) + 12*(1/4)/-4
---
Question: It is hard to tell what the "x" is the denominator of.
So I'm just going to leave it there. Hopefully you know what it
is deviding.
-------
= -4 + 3/(-4)
===============================
Cheers,
Stan H.
PS: Reply to stanbon@comcast.net as the algebra.com
feedback program is not working.

===============================